I extracted the numbers of the last 26 euromillion lottery results. So I had around 2 sets of numbers. The first set contained the numbers which resulted after grouping the first 5 numbers of each result and the next set contained the numbers which resulted after grouping the last 5 numbers of each result. I did this because in Euromillions, the result of a lottery is a group of 7 number. Each of the first 5 numbers can be between 1 to 50 and each of the last two numbers can be between 1 to 9. Then for each set I found out which number has repeated itself how many times. Then I ordered this result in ascending order of the repetitions of the numbers. When I compared the results I found that the latest result was in the lower half of the list of numbers ordered in ascending order.
As a real example, the following numbers were the results of the last 26 draws of the national lottery:
38 39 45 46 49 7 8
9 24 37 39 49 3 9
12 13 36 41 46 1 8
1 8 18 28 31 8 9
2 29 31 32 38 1 4
2 22 24 36 44 1 2
4 17 34 40 42 4 9
4 9 31 32 33 3 7
7 19 30 38 50 4 7
1 17 31 43 47 2 3
3 6 15 21 32 7 9
6 22 24 25 36 3 8
3 7 8 43 46 6 8
9 11 17 26 40 3 9
7 21 23 24 44 3 4
12 18 24 26 45 4 5
8 16 18 37 43 2 6
10 28 30 38 39 2 7
1 26 33 36 46 6 7
12 18 19 43 49 3 9
7 11 18 29 42 6 7
12 31 37 38 43 2 3
1 5 18 38 45 4 6
34 35 38 39 46 3 4
9 17 30 39 43 5 7
4 22 27 36 44 7 9
Now for the first set of 5 number's affter finding out which number repeated how many times, I had the following:
@10@ 1
@13@ 1
@15@ 1
@16@ 1
@23@ 1
@25@ 1
@27@ 1
@35@ 1
@41@ 1
@47@ 1
@50@ 1
@5@ 1
@11@ 2
@19@ 2
@21@ 2
@28@ 2
@29@ 2
@2@ 2
@33@ 2
@34@ 2
@3@ 2
@40@ 2
@42@ 2
@6@ 2
@22@ 3
@26@ 3
@30@ 3
@32@ 3
@37@ 3
@44@ 3
@45@ 3 <---
@49@ 3 <---
@4@ 3
@8@ 3
@12@ 4
@17@ 4
@1@ 4
@7@ 4
@9@ 4
@24@ 5
@31@ 5
@36@ 5
@39@ 5 <---
@46@ 5 <---
@18@ 6
@43@ 6
@38@ 7 <----
And for the 2nd set of 2 number's affter finding out which number repeated how many times, I had the following:
@5@ 2
@1@ 3
@2@ 5
@6@ 5
@8@ 5 <---
@4@ 7
@9@ 7
@3@ 9
@7@ 9 <---
And the latest result was :
38 - 39 - 45 - 46 - 49 7 - 8
If you look at the results, the lower half of the numbers has a more density of the winning numbers. So, if you select you numbers from the lower half (especially from the bottom most part), you have a high chance of winning. Note that the above list of numbers ordered according to their repetitions, will keep changing according to the results of each draw. I wrote the following 2 unix scripts ( computer programs / software) to get these statistics:
cat find_count.sh
sort gir_lu | uniq >> ./temp_sort
while read var
do
count=`grep $var gir_lu | wc -l`
echo $var " " $count >> ./temp_list
done < ./temp_sort
sort -n -t ' ' +2 temp_list
rm -i temp_list temp_sort
cat find_count2.sh
sort gir_lu2 | uniq >> ./temp_sort
while read var
do
count=`grep $var gir_lu2 | wc -l`
echo $var " " $count >> ./temp_list
done < ./temp_sort
sort -n -t ' ' +2 temp_list
rm -i temp_list temp_sort
cat gir_lu
#these numbers are one below the other displayed incorrectly here.
@38@ @39@ @45@ @46@ @49@ @9@ @24@ @37@ @39@ @49@ @12@ @13@ @36@ @41@ @46@ @1@ @8@ @18@ @28@ @31@ @2@ @29@ @31@ @32@ @38@ @2@ @22@ @24@ @36@ @44@ @4@ @17@ @34@ @40@ @42@ @4@ @9@ @31@ @32@ @33@ @7@ @19@ @30@ @38@ @50@ @1@ @17@ @31@ @43@ @47@ @3@ @6@ @15@ @21@ @32@ @6@ @22@ @24@ @25@ @36@ @3@ @7@ @8@ @43@ @46@ @9@ @11@ @17@ @26@ @40@ @7@ @21@ @23@ @24@ @44@ @12@ @18@ @24@ @26@ @45@ @8@ @16@ @18@ @37@ @43@ @10@ @28@ @30@ @38@ @39@ @1@ @26@ @33@ @36@ @46@ @12@ @18@ @19@ @43@ @49@ @7@ @11@ @18@ @29@ @42@ @12@ @31@ @37@ @38@ @43@ @1@ @5@ @18@ @38@ @45@ @34@ @35@ @38@ @39@ @46@ @9@ @17@ @30@ @39@ @43@ @4@ @22@ @27@ @36@ @44@
cat gir_lu2
#these numbers are one below the other displayed incorrectly here.
@7@ @8@ @3@ @9@ @1@ @8@ @8@ @9@ @1@ @4@ @1@ @2@ @4@ @9@ @3@ @7@ @4@ @7@ @2@ @3@ @7@ @9@ @3@ @8@ @6@ @8@ @3@ @9@ @3@ @4@ @4@ @5@ @2@ @6@ @2@ @7@ @6@ @7@ @3@ @9@ @6@ @7@ @2@ @3@ @4@ @6@ @3@ @4@ @5@ @7@ @7@ @9@
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